#108703: "Tiebreak when the instant win card is activated"
O czym jest to zgłoszenie?
Co się stało? Wybierz z poniższych opcji
Co się stało? Wybierz z poniższych opcji
Sprawdź, czy istnieje już zgłoszenie na ten sam temat
Jeśli tak, ZAGŁOSUJ na to zgłoszenie. Zgłoszenia z największą liczbą głosów mają najwyższy PRIORYTET!
| # | Status | Votes | Game | Type | Title | Last update |
|---|
Szczegółowy opis
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• Proszę skopiować i wkleić treść błędu wyświetloną na ekranie, o ile jakaś się pojawia.
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. -
• Proszę opisać co chciałeś zrobić, co zrobiłeś i co się stało
End of game standings
• Jaką masz przeglądarkę?
Google Chrome v120
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• Proszę skopiować i wkleić tekst wyświetlany w języku angielskim zamiast w twoim języku. Jeśli posiadasz zrzut ekranu przedstawiający ten błąd (dobra praktyka), możesz skorzystać z wybranej przez siebie usługi hostującej zdjęcia (np. snipboard.io), aby go przesłać, a następnie skopiuj i wklej link tutaj. Czy ten tekst jest dostępny w systemie tłumaczeń? Jeśli tak, to czy został przetłumaczony więcej niż 24 godziny temu?
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • Jaką masz przeglądarkę?
Google Chrome v120
-
• Wyjaśnij swoją propozycję precyzyjnie i zwięźle, tak aby jak najłatwiej zrozumieć, co masz na myśli.
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • Jaką masz przeglądarkę?
Google Chrome v120
-
• Co wyświetlało się na ekranie kiedy zostałeś zablokowany (Pusty ekran? Część interfejsu gry? Komunikat o błędzie?)
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • Jaką masz przeglądarkę?
Google Chrome v120
-
• Która z zasad gry nie była przestrzegana w adaptacji BGA
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. -
• Czy naruszenie zasad gry jest widoczne w powtórce rozgrywki? Jeżeli tak, to w ruchu o jakim numerze?
End of game standings
• Jaką masz przeglądarkę?
Google Chrome v120
-
• Jaką akcję w grze chciałeś wykonać?
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. -
• Co starasz się zrobić by uruchomić tę akcję w grze?
End of game standings
-
• Co się stało kiedy próbowałeś to zrobić (komunikat o błędzie, komunikat na pasku stanu gry, ...)?
• Jaką masz przeglądarkę?
Google Chrome v120
-
• W którym momencie gry pojawił się problem (jakie było aktualne polecenie w grze)?
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. -
• Co się stało kiedy próbowałeś wykonać akcję w grze (komunikat o błędzie, komunikat na pasku stanu gry, ...)?
End of game standings
• Jaką masz przeglądarkę?
Google Chrome v120
-
• Proszę opisać problem z wyświetlaniem. Jeśli posiadasz zrzut ekranu przedstawiający ten błąd (dobra praktyka), możesz skorzystać z wybranej przez siebie usługi hostującej zdjęcia (np. snipboard.io), aby go przesłać, a następnie skopiuj i wklej link tutaj.
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • Jaką masz przeglądarkę?
Google Chrome v120
-
• Proszę skopiować i wkleić tekst wyświetlany w języku angielskim zamiast w twoim języku. Jeśli posiadasz zrzut ekranu przedstawiający ten błąd (dobra praktyka), możesz skorzystać z wybranej przez siebie usługi hostującej zdjęcia (np. snipboard.io), aby go przesłać, a następnie skopiuj i wklej link tutaj. Czy ten tekst jest dostępny w systemie tłumaczeń? Jeśli tak, to czy został przetłumaczony więcej niż 24 godziny temu?
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • Jaką masz przeglądarkę?
Google Chrome v120
-
• Wyjaśnij swoją propozycję precyzyjnie i zwięźle, tak aby jak najłatwiej zrozumieć, co masz na myśli.
When two players have the same number of coins at the end of the game, the player who scored more points on the last round is considered to beat the player who scored fewer points.
In this game, the instant win card (least frequent > most frequent) happened, and a player won. The other two players had 2 coins each at the time. At the end of the game scoreboard, both players were listed as having 0 coins in the last round. It's unclear to me whether the last round should have been the round in which the instant win card was played or the round before, but in neither case did both players have 0 coins. (Also worth noting - nobody was awarded coins that round, which is probably intentional?).
When the instant win card is successfully played, the game should use the tiebreaker (either from the current round or the previous) rather than randomly assigning placement. • Jaką masz przeglądarkę?
Google Chrome v120
Historia zgłoszeń
For me, when someone instant win, then all others having 0 will tie them second (that's what happened to you, this is not random placement).
Dodaj coś do tego zgłoszenia
- Kolejne ID stołu / ID ruchu
- Czy F5 rozwiązało problem?
- Czy problem zdarzył się kilka razy? Za każdym razem? Losowo?
- Jeśli posiadasz zrzut ekranu przedstawiający ten błąd (dobra praktyka), możesz skorzystać z wybranej przez siebie usługi hostującej zdjęcia (np. snipboard.io), aby go przesłać, a następnie skopiuj i wklej link tutaj.
